df回弹补偿的问题？

BEFORE SPRINGBACK
导入或选择回弹前的板料模型。用户可以导入dynain格式的文件。
AFTER SPRINGBACK
导入或选择回弹后的板料模型。用户可以导入dynain格式的文件。
DESIRED SHAPE
导入或选择期望得到的板料形状。用户可以导入dynain格式的文件。该形状一般为回弹前的形状。
COMPENSATED SHAPE
导入或选择补偿后的板料形状。用户可以导入dynain、*.tmp等格式的文件。当进行第一次回弹补偿计算时，该形状为回弹前的板料形状。在第二次及后续迭代中，用户应导入补偿后的“disp.tmp”文件并将其定义为补偿后的板料形状。
我输入后计算error。显示信息如下：
The native file format : 32-bit small endian
Memory size from command line: 67108864
expanding memory to 67108864 starting ls-dyna
******** notice ******** notice ******** notice ********
* *
* This is the LS-DYNA Finite Element code. *
* *
* Neither LSTC nor the authors assume any responsibility for *
* the validity, accuracy, or applicability of any results *
* obtained from this system. The user must verify his own *
* results. *
* *
* LSTC endeavors to make the LS-DYNA code as complete, *
* accurate and easy to use as possible. *
* Suggestions and comments are welcomed. Please report any *
* errors encountered in either the documentation or results *
* immediately to LSTC through your site focus. *
* *
* Copyright (C) 1990-2008 *
* by Livermore Software Technology Corp. (LSTC) *
* All rights reserved *
* *
******** notice ******** notice ******** notice ********
contracting memory to 1 beginning of keyword reader
expanding memory to 20100
expanding memory to 383728
expanding memory to 428728
expanding memory to 458728
expanding memory to 1873900
expanding memory to 1991831
expanding memory to 2450585
expanding memory to 2906309
expanding memory to 3931703
E r r o r t e r m i n a t i o n
s t o r a g e a l l o c a t i o n
Memory required to complete solution : 3931703
Additional dynamically allocated memory: 0
Total: 3931703
T i m i n g i n f o r m a t i o n
CPU(seconds) %CPU Clock(seconds) %Clock
----------------------------------------------------------------
Initialization ....... 0.0000E+00 0.00 0.0000E+00 0.00
Element processing ... 0.0000E+00 0.00 0.0000E+00 0.00
Binary databases ..... 0.0000E+00 0.00 0.0000E+00 0.00
ASCII database ....... 0.0000E+00 0.00 0.0000E+00 0.00
Contact algorithm .... 0.0000E+00 0.00 0.0000E+00 0.00
Contact entities ..... 0.0000E+00 0.00 0.0000E+00 0.00
Rigid bodies ......... 0.0000E+00 0.00 0.0000E+00 0.00
Implicit Nonlinear ... 0.0000E+00 0.00 0.0000E+00 0.00
Implicit Lin. Alg. ... 0.0000E+00 0.00 0.0000E+00 0.00
----------------------------------------------------------------
T o t a l s 0.0000E+00 0.00 0.0000E+00 0.00
Problem time = 0.0000E+00
Problem cycle = 0
Total CPU time = 0 seconds ( 0 hours 0 minutes 0 seconds)
CPU time per zone cycle = 0 nanoseconds
Clock time per zone cycle= 0 nanoseconds
Number of CPU's 0
NLQ used/max 96/ 96
Start time 09/27/2008 11:03:40
End time 09/27/2008 11:03:43
Elapsed time 3 seconds( 0 hours 0 min. 3 sec.) for 0 cycles
E r r o r t e r m i n a t i o n
请问这是怎么回事啊？
还有，请问工具输入里的主零件层和从工具 输入什么东西啊？