NASTRAN灵敏度分析f06文件错误

这个是我的bdf文件中灵敏度分析的卡片
$ ...DESIGN VARIABLE DEFINITION
$ Alu_dtm_Elastic_Modulus
DESVAR,1,V1,1.,0.5,2.,0.5
$ Alu_dtm_flb_mz_Elastic_Modulus
DESVAR,2,V2,1.,0.5,2.,0.5
$ ...DEFINITION OF DESIGN VARIABLE TO ANALYSIS MODEL PARAMETER RELATIONS
DVMREL1,1,MAT1,11,E, , ,0.,
,1,7.+10
DVMREL1,2,MAT1,16,E, , ,0.,
,2,5.7+10
$ ...STRUCTURAL RESPONSE IDENTIFICATION
DRESP1,1,WEIGHT,WEIGHT,,,,
DRESP1,2,MODE7,FREQ,,,7,
DRESP1,3,MODE8,FREQ,,,8,
DCONSTR, 1,1,-1.,-0.5,,
DCONSTR, 2, 2, -0.01, 10, ,
DCONSTR, 2, 3, -0.01, 10, ,
提交给nastran计算,f06文件提示错误如下
----- COMPARISON BETWEEN INPUT MATERIAL PROPERTY VALUES FROM ANALYSIS AND DESIGN MODELS -----
---------------------------------------------------------------------------------------------------------------
MATERIAL MATERIAL MATERIAL ANALYSIS DESIGN LOWER UPPER DIFFERENCE
TYPE ID NAME VALUE VALUE BOUND BOUND FLAG
---------------------------------------------------------------------------------------------------------------
MAT1 11 E 7.000000E+10 7.000000E+10 N/A N/A NONE
MAT1 16 E 5.700000E+10 5.700000E+10 N/A N/A NONE
1. THE DIFFERENCE FLAG IS USED TO CHARACTERIZE DIfFERENCES BETWEEN ANALYSIS AND DESIGN MODEL PROPERTIES:
IF THE FLAG IS NONE, THEN THERE IS NO SIGNIFICANT DIFFERENCE BETWEEN THE TWO VALUES.
IF THE FLAG IS WARNING, THEN THE USER IS ADVISED THAT DIFFERENCES EXIST AND THE DESIGN MODEL
IS BEING USED TO OVERRIDE THE ANALYSIS MODEL.
IF THE FLAG IS FATAL, THEN THE DIFFERENCES ARE GREATER THAN 1.00000E+35 AND THE RUN WILL BE TERMINATED.
*** USER WARNING MESSAGE 7409 (DOPR1J)
EQUATION: E = 2*(1+NU)*G MAY BE VIOLATED FOR MAT1 ENTRY ID = 11 REFERRED BY DVMREL1 AND/OR DVMREL2 ENTRIES.
USER INFORMATION: THE CORRESPONDING SENSITIVITY COEFFICIENTS MAY BE INACCURATE.
USER ACTION: LEAVE AT LEAST ONE OF THE THREE VALUES (E, G, NU) BLANK AND UNREFERRED BY A DVMREL1/DVMREL2 ENTRIES
看了好久不知道怎么改,请高手指点。
另外有没有正在做nastran优化的,有的话加我qq 409611137 一起交流!
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共5个回答

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  • 邹正刚
    2009年9月13日
    MAT1 卡的格式不对:
    MAT1 11 E 7.000000E+10 7.000000E+10 N/A N/A NONE
    其中第 3 到 5 个域分别是 E, G ,Nu 的值,而不能是字符 "E",此外,这 3 个值只能填写两个,第 3 个有程序自动计算。再有,你的 MAT1 卡中有两个 7.000000E+10 ,无论他们代表 E, G, Nu 的哪两个都是不合理的,无法算出第 3 个合理的值。
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  • 马伟标
    2009年11月26日
    有关于灵敏度分析的资料吗?
    0评论 采纳答案 举报

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