应力波基础_第2版_王礼立_2005.pdf

节选段落一：
C( =wik =fA )rti:P~r«JJE:
C2 C2 2 2 2 cij
= 0 - II rgW = 1 2 2k2+ II r g
(2 - 68a)
(2 - 68b)
~ 112 rik2 < 1at, J1i:M:l&1f
s 1-( k)2 22(!Jl)2Co = 1 - 2 IIrg = 1 - 211 1[" ;.
xtr~~£1g a B"JWl1ttff, rg = ad2,~~
~ = 1 _ 112~( ~ )2 (2 _ 68c)
J!ttH::~m3!lJm[PJ·tIJ!


节选段落二：
[jJljJt(2 -71) ,!J!IJ1f
aw C2 ae
at = Tax
x
(2 - 73)
(2 - 74)
(2 - 75)
(2 - 76)
(2 - 77)
CT =~ (2 -78)
Jt(2 -70)~Jt(2 -77):J!LV.1bitll w ~.{\Lm~1b e1:J*~p]j!fiI'fJ-IDr~dBlli!fAiHfHtjJ
~m ,tE~Jt..t.!§m.tlUlit9=' EE Jt(2 - 12)~Jt(2 - 16)J9TmJVtl'fJjJ~!Jl7t~-!L !


节选段落三：
Jj~(Yang LM, Shim P,V W,2005)i!~ili~nrm*~*(MT k~3):
.2f[1 _ (_ ~)k]
,ak = 2kf3_1+(~~~)k
)(ij"T~1iiJ1¥.J f3 '{OC(f3 =112,114,116,1110,1125 ,111(0), 11i:...tJ:ti-t1!l=J9ft~1¥.J ak Mi k 1£1t1¥.J
ta*~llm 3- 19 FRlRo El:ultliJ!\!., :I1fmAM7lttfl ak-k dIl~·tf!.IIjfHJ.tlm.:mIt f3I¥.J(IIJl/j\ iJiir
~,{§.I!